4.9t^2-6t-50=0

Solution for 4.9t^2-6t-50=0 equation:

4.9t^2-6t-50=0

a = 4.9; b = -6; c = -50;
Δ = b2-4ac
Δ = -62-4·4.9·(-50)
Δ = 1016
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1016}=\sqrt{4*254}=\sqrt{4}*\sqrt{254}=2\sqrt{254}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{254}}{2*4.9}=\frac{6-2\sqrt{254}}{9.8}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{254}}{2*4.9}=\frac{6+2\sqrt{254}}{9.8}
$